Circular Orbit
Velocity of Circular Orbit
We're going to look at circular orbit. Imagine a satellite with mass m orbiting a planet, which has mass M. It is at a distance r from the centre of the planet. It is moving at velocity v, at right angles to the planet, and this velocity allows the outward centrifugal force Fcent to just about balance the gravitational force Fgrav. Thus
Fgrav = Fcent
$$ \frac{GMm}{r^2} = \frac{mv^2}{r} $$
Rearranging for v:
$$ v = \sqrt{\frac{GM}{r}} $$
This is the speed the satellite needs to be travelling in order to maintain circular orbit.
Orbital Period
The orbital period T is the time taken for the satellite to complete a single orbit. For a circular orbit, multiplying the velocity by the time taken equals the circumference of the circular orbit:
$$ vT = 2 \pi r $$
Rearranging for T, and substituting the equation for velocity:
$$ T = \frac{2 \pi r }{v} = 2 \pi r \sqrt{\frac{r}{GM}} $$
This is the equation for the orbital period of a satellite orbiting a body of mass M at a distance r from its centre:
$$ T = \frac{2 \pi }{\sqrt{GM}}r^{\frac{3}{2}} $$
Back to Astronomy